x=12(0.3+0.5)(15+0.5)*0.02+1*0.5*0.5*0.02-0.5*(0.3+0.5)*0.04/0.5^2*(0.3+0.5)^2

Solution for x=12(0.3+0.5)(15+0.5)*0.02+1*0.5*0.5*0.02-0.5*(0.3+0.5)*0.04/0.5^2*(0.3+0.5)^2 equation:

x=12(0.3+0.5)(15+0.5)*0.02+1*0.5*0.5*0.02-0.5(0.3+0.5)*0.04/0.5^2(0.3+0.5)^2

We move all terms to the left:

x-(12(0.3+0.5)(15+0.5)*0.02+1*0.5*0.5*0.02-0.5(0.3+0.5)*0.04/0.5^2(0.3+0.5)^2)=0

We add all the numbers together, and all the variables

x-(12(0.8)(15.5)*0.02+1*0.5*0.5*0.02-0.5(0.8)*0.04/0.5^2(0.8)^2)=0

We multiply parentheses ..

x-(12()*0.02+1*0.5*0.5*0.02-0.5(0.8)*0.04/0.5^2(0.8)^2)=0

We multiply all the terms by the denominator


x*0.5^2(0.8)^2)-(12()*0.02+1*0.5*0.5*0.02-0.5(0.8)*0.04=0

We add all the numbers together, and all the variables

x*0.5^2(0.8)^2)-(12()*0.02-0.011=0

Wy multiply elements

0x^2-0.011=0

We add all the numbers together, and all the variables

x^2-0.011=0

a = 1; b = 0; c = -0.011;
Δ = b2-4ac
Δ = 02-4·1·(-0.011)
Δ = 0.044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.044}}{2*1}=\frac{0-\sqrt{0.044}}{2}
=-\frac{\sqrt{}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.044}}{2*1}=\frac{0+\sqrt{0.044}}{2}
=\frac{\sqrt{}}{2}
$